When a watermelon is launched into the air, it forms a parabola y = −2x 2+120x+2000y, and the line equation of the watermelon launcher to the land is y=150x. Solve the system of equations by substitution. So, in the 5 th month from the starting, the sales are same. The sales the of the first product are y = −x 2−10x+25y and the sales of the second product are y = 14x−119y In which month do the sales are same? The sales of the two products are the same in a particular month. In the substitution method, we substitute the linear equation in the quadratic equation in the place of the variable ‘y’ and we will write the like terms on one side, and we will continue the process of the quadratic equation by factoring.Ī textile company has launched two products in the same month. We can solve the system of linear and quadratic equations also by using the substitution method. Solving System of Equations using Substitution The solutions of the system of equations are (-2, 1) and (-3, 0).
Given system of equations are: y = 2+6x+9 … (1) The solutions of the system of equations are (0, 4) and (5, 9). Now we eliminate the variable ‘y’ from the system of equationsīy substituting x value in the system of equation, we get Given system of equations are: y = x²-4x+4… (1)
In the elimination method, we subtract the linear equation and the quadratic equation to eliminate the variable ‘y’ and we will write the like terms on one side.įind the solutions for the system of equation We can solve system of linear and quadratic equations by using elimination method. Solving System of Equations using Elimination
We verified that the solution of the linear-quadratic equation as x = 2 and y =10. Now, we will check by substituting in the equation x 2+6 = 4x+2. The line and parabola intersect at one point (2, 10)